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1.5x^2+2x-357=0
a = 1.5; b = 2; c = -357;
Δ = b2-4ac
Δ = 22-4·1.5·(-357)
Δ = 2146
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{2146}}{2*1.5}=\frac{-2-\sqrt{2146}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{2146}}{2*1.5}=\frac{-2+\sqrt{2146}}{3} $
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